Question 573842
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I have no idea how you would solve it.  All I can tell you is how I would solve it, but bear in mind that there are at least 3 other equally valid ways to do it.


Add 3 to both sides of the first equation giving you an expression in *[tex \Large x] that is equal to *[tex \Large y].  Substitute this expression in place of *[tex \Large y] in the second equation.  You will now have a single variable equation in *[tex \Large x].  Collect terms and solve for *[tex \Large x].  Take this newly discovered value for *[tex \Large x] and substitute it back into the first equation giving you a single variable equation in *[tex \Large y].  Solve it.


You now have a value for *[tex \Large x] and a value for *[tex \Large y].  Substitute both values into each of the original equations to check your work.  If you have done the arithmetic correctly, then in each case the result is a true statement.


Given a successful check step, form the ordered pair *[tex \Large (x,y)] with the values determined.  Your solution set consists of the single element of the ordered pair just formed.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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