Question 54598
Which of the ordered pairs 
	(–7, 2), (1, 0), (–3, –1), (–23, 6)
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are solutions for the equation x + 4y = 1?
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Each ordered pair represents the values of x & y.
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Substitute the values for x & y and see if the equation is true;
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The first pair: (-7,2), substitute these value for x & y in x + 4y = 1
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     -7 + 4(2) = 
     -7 +  8   = 1, so the 1st pair is a solution
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The 2nd pair: (1,0)
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          1 + 4(0) = 1
          1 + 0 = 1 so the 2nd pair is also a solution
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The 3d pair: (-3,-1)
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      -3 + 4(-1) = 1
          -3 - 4 = -7 so this is not a solution
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The 4th pair: (-23,6)
:      -23 + 4(6) = 1
       -23 + 24  = 1 so this is a solution also