Question 573348
<pre>
3x³-15x²-6x+30

Factor out 3, using brackets:

3[x³-5x²-2x+10]

Factor the first two terms in the brackets by factoring out x²
Factor the last two terms by factoring out -2

3[x²(x-5)-2(x-5)]

Factor out the (x-5) inside the brackets, leaving the x² and the
-2 to put inside a parentheses:

3[(x-5)(x²-2)]

Erase the brackets:

3(x-5)(x²-2)

Edwin</pre>