Question 573120
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When you start, the rear of the army is APPROACHING you at 3 mph and you are traveling 5 mph for a total rate of 8 mph.  Using time equals distance divided by rate, it takes you 5/8 of an hour to get to the rear of the column.


On the way back, the front of the army is moving AWAY from you at 3 mph and you are traveling 5 mph for a total rate of 2 mph.  T = D/R again, so 5/2 hour to get back to the front.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{8}\ +\ \frac{5}{2}\ =]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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