Question 572964
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I'm not sure what you did wrong exactly because the rendering of your work just doesn't line up so that it is understandable.  But let me show you where you should have been following your line of reasoning.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4y\ +\ 3\ =\ 3y\ +\ x]


Add *[tex \Large -4y] and *[tex \Large -x] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4y\ -\ 4y\ +\ 3\ -\ x\ =\ 3y\ -\ 4y\ +\ x\ -\ x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3\ -\ x\ =\ -y]


Multiply by -1


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ 3\ =\ y]


Now substitute *[tex \Large x\ -\ 3] for *[tex \Large y] in the second equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ 4(x\ -\ 3)\ =\ 18]


Solve for *[tex \Large x], then substitute back into either original equation and solve for *[tex \Large y].


And NEVER, NEVER, NEVER again even THINK about dividing ANYTHING by zero.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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