<PRE><B>Question 572423</B>
The slope of the radius connecting those two points is


*[tex \LARGE m = \frac{0-9}{2-4} = \frac{9}{2}].


Since the line tangent to the circle is perpendicular to this radius, the slope of the tangent line will be -1/m, or -2/9. We know that (4,9) is on the desired line so we can write in point-slope form:


*[tex \LARGE y - 9 = -\frac{2}{9}(x - 4)]</PRE>