Question 572842
{{{(5/(y-3))+ (10/(y^2-y-6)) = (y/(y+2))}}}

{{{(5/(y-3))+ (10/((y-3)(y+2))) = (y/(y+2))}}}

Multiply by (y-3)(y+2)

5(y+2) +10 =y(y-3)

5y+10+10=y^2-3y

5y+20=y^2-3y

y^2-8y-20=0

y^2-10y+2y-20=0
y(y-10)+2(y-10)=0
(y-10)(y+2)=0
y=10 OR -2