Question 572732
{{{ x = log(125,(1/5)) }}}
I can rewrite this as:
{{{ 125^x = 1/5 }}}
{{{ (5^3)^x = 1/5 }}}
{{{ 5^(3x) = 1/5 }}}
Take the log to the base 5 of both sides
{{{ log( 5,(5^(3x))) = log(5,(1/5)) }}}
{{{ 3x = -1 }}}
{{{ x = -(1/3) }}}