Question 54592
These are the steps you will use for both of your problems.
Isolate the absolute value on one side of the inequality sign.  
If the inequality sign is now |x|>k, solve two problems for x: x>k or x<-k.
:
62)
{{{(1/3)*abs(2x-1)>1}}}
{{{3(1/3)*abs(2x-1)>3(1)}}}
{{{abs(2x-1)>3}}}
{{{2x-1>3}}} or {{{2x-1<-3}}}
{{{2x-1+1>3+1}}} or {{{2x-1+1<-3+1}}}
{{{2x>4}}} or {{{2x<-2}}}
{{{2x/2>4/2}}} or {{{2x/2<-2/2}}}
{{{x>2}}} or {{{x<-1}}}
:
72)
This one is solvable without solving it |x|>-k is all real numbers, the opposite |x|<-k is no solution.  Because absolute values result in positive numbers.  Let's solve it for fun anyways:
{{{abs(3x-7)>-3}}}
{{{3x-7>-3}}} or {{{3x-7<3}}}
{{{3x-7+7>-3+7}}} or {{{3x-7+7<3+7}}}
{{{3x>4}}} or {{{3x<10}}}
{{{3x/3>4/3}}} or {{{3x/3<10/3}}}
{{{x>4/3}}} or {{{x<10/3}}}
That is all real numbers, let me show you why on a number line:
x>1 1/3 or x< 3 1/3
<<=======[============]=======>>
-1,0,1,1 1/3, 2, 3, 3 1/3, 4
I know it's hard to see, but the whole number line is shaded.

Happy Calculating!!!