Question 572258
"Length" by itself is not used in describing a triangle. At most, "length of" a side, or a leg could be expected. I imagine that they mean something like this:
{{{drawing(300,200,-2,19,-3,11,
triangle(0,0,16,0,16,8),
locate(8,0,2x),locate(16.2,4.5,x)
)}}} I would say the base of that triangle is twice its height, or that one leg of the right triangle is twice as long as the other leg.
In that case, the problem is easy because you would know the base (2x) and the height (x) of the triangle.
As the area of a triangle ia half of the product of base times height, the area would be
{{{(1/2)*(2x)*x=25}}} --> {{{x^2=25}}} so {{{x=5}}} and {{{2x=10}}}.
I guess they expect you to draw on grid paper so that the short leg is 5 units long (5 squares) and the long leg is 10 units long (10 squares).
If what they mean by the base and the "length" of the triangle are not the two sides that make a right angle, then it is way too complicated a problem for a class where areas are measured in "square units".