Question 572314
8/ (3+6i) in a+bi form
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Multiply numeraor and denominator by 3-6i to get:
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[8(3-6i)]/[(3+6i)(3-6i)]
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[24-48i]/(9+36)
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=[24-48i]/45
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= (8/15) - (16/15)i
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Cheers,
Stan H.
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