Question 54523
john's age is four less than six times his brother's age and the sum of thier ages is equal to ten. how do you slove this word proublem?
ans: let john's age = x years
john's brother's age = y years.
then according to the problem    x = 6*y-4 ----I
                        and  x + y = 10 --------II                   
                           Putting x from I in II
                             6y-4+y=10
                             7y=14
                         hence y=2years
                            and x=8years