<PRE><B>Question 572263</B>
y = 5(x+5)(x-2)

y = 5(x^2 + 3x - 10)

y = 5x^2 + 15x - 50

The vertex we need is in the form (x,y).


To find the x-coordinate, use x = -b/2a.


a = 5 and b = 15


x = -15/2(5)


x = -15/10


x = -3/2


To find y, replace x in the above equation with -3/2 and simplify.


y = 5(-3/2)^2 + 15(-3/2) - 50


y =  -245/4


The vertex is the pont (-3/2, -245/4).




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