Question 571894
The diameters of grapefruits in a certain orchard are normally distributed with a mean of 6.45 inches and a standard deviation of 0.45 inches. Show all work. 
(A) What percentage of the grapefruits in this orchard have diameters less than 7.1 inches? 
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z(7.1) = (7.1-6.45)/0.45 = 1.4444
P(x < 7.1) = P(z < 1.4444) = normalcdf(-100,1.4444) = 0.9257 = 92.57%
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(B) What percentage of the grapefruits in this orchard are larger than 6.8 inches? 
Comment: Use the same procedure on this problem
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cheers,
Stan H.