Question 571031
We have two equations in two unknowns.


a + b = 54


a*b = 665


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Solving a + b = 54 for a, I get a = 54 - b.


I then plug 54 - b in the equation a*b = 665.


(54 - b)*b = 665


I proceed to solve (54 - b)*b = 665 for b.

Solving for b, I get two answers: b = 19 and b = 35.

To find a, I must replace either original equation with either value of b.

I will use b = 19.


a + b = 54


a + 19 = 54

a = 54 - 19


a = 35.


The numbers are 19 and 35.