Question 54362
n = number of Natalies nickels
d = number of Dirks dimes
q = number of Quincys quarters
5n + 10d + 25q = the sum of all their coins
d = q + 5
5n - 5 + 25 = 10d + 5 - 10 = 25q - 25 + 10
5n + 20 = 10d - 5 = 25q - 15
since d = q + 5
10(q + 5) - 5 = 25q - 15
10q + 45 = 25q - 15
15q = 60
q = 4 answer
d = q + 5
d = 9 answer
5n + 20 = 10d - 5
5n = 10*9 - 5 - 20
5n = 65
n = 13 answer
5n + 10d + 25q = the sum of all their coins
5*13 + 10*9 + 25*4 = 255
each person ends up with 255/3 = 85
5n + 20 = 5*13 + 20 = 85
10d - 5 = 10*9 - 5 = 85
25q - 15 = 25*4 - 15 = 85
so they all end up with an equal share