Question 570869
{{{2^n=sqrt(3^(n-2))}}}
Square both sides
{{{2^(2n) = 3^(n-2)}}} assuming n-2 is the exponent.  Use parentheses.
2n*log(2) = (n-2)*log(3) = nlog(3) - log(9)
2n*log(2) - n*log(3) = -log(9)
n*(log(3) - 2log(2)) = log(9)
n = log(9)/log(3/4)
n =~ -7.6377