Question 570838
{{{a=b-3}}}
{{{a^2+b^2=65}}}
.
{{{(b-3)^2+b^2=65}}}
{{{b^2-6b+9+b^2=65}}}
{{{2b^2-6b+9=65}}}
{{{2b^2-6b-56=0}}}
{{{2(b^2-3b-28)=0}}}
find two numbers that multiply to get -28 and add to get -3
-7 and 4
{{{2(b-7)(b+4)=0}}}
{{{b=7}}},{{{-4}}}
plug the b's into the first equation
{{{a=4}}},{{{-7}}}
if you cant understand the quick solve above there's always the long quadratic solution below
*[invoke quadratic "b", 1, -3, -28]