Question 570750
1. 4x-16y=2

16y=4x-2

/16
y=(1/4)x-(1/8)

slope of this line is (1/4)

The parallel line will have same slope = 1/4
point = (-2,-6)

Find b , plug point and slope in the equation y = mx+b

-6=(1/4)(-2)+b
-6=(-1/2)+b
-6+1/2=b
b=-5 1/2

b= -11/2

Equation ; y= (1/4)x-11/2

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4	x		-16	y  	=	2				
Find the slope of this line 										
										
-16	y  	=	-4	x	+	2				
Divide by 	-16									
	y  	=	0.250	x	+	-0.13				
Compare this equation with y=mx+b										
slope m =	1/4									
										
The slope of a line perpendicular to the above line will be the negative reciprocal -4
m1*m2=-1										
The slope of the required line will be 	-4											
m=	-4    	,point	(	-2	,	-6	)			
Find b by plugging the values of m & the point in										
y=mx+b										
-6	=	8	+	b						
b=	-14									
m=	-4    									
The required equation is y  =-4x-14      			
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