Question 54493
f(x) = 3x^2 - 4x - 3
f(x - 1) = 3(x - 1)^2 - 4(x - 1) - 3
f(x - 1) = 3(x^2 - 2x + 1) - 4x + 4 - 3
f(x - 1) = 3x^2 - 6x + 3 - 4x + 1 = 3x^2 - 10x + 4