Question 570382
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Let *[tex \Large x] represent the measure of the complement of the angle.  Then twice the measure of the complement is *[tex \Large 2x] and 15 more than that is *[tex \Large 2x\ +\ 15].  Since the sum of the measures of complementary angles is 90, if *[tex \Large x] is the measure of the complement, then *[tex \Large 90\ -\ x] must be the measure of the angle.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ 15\ =\ 90\ -\ x]


Solve for *[tex \Large x] then calculate *[tex \Large 90\ -\ x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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