Question 570369
 Ten years from now, A will be twice as old as B. Five years ago, A was three times as old as B. What are the present ages of A and B?
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Equations:
(A+10) = 2(B+10)
(A-5) = 3(B-5)
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Rearrange:
A - 2B = 10
A - 3B = -10
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Subtract and solve for "B":
B = 20
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Solve for "A":
A = 2B+10
A = 2*20+10
A = 50
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cheers,
Stan H.