Question 570103
A basket contains many apples and the apples are divided among six people.
 One third, one fourth, one eighth, and one fifth of the apples are given to the first four people, respectively.
 The fifth person gets ten apples and the sixth person gets one apple.
 Find the original number of apples in the basket.
I tried the following: Let A = Original number of apples
:
You don't need x here.
:
A = {{{1/3}}}A + {{{1/4}}}A + {{{1/8}}}A + {{{1/5}}}A + 10 + 1
Find the Common denominators of all these fractions, that would be 120, as you said 
A = {{{40/120}}}A + {{{30/120}}}A + {{{15/120}}}A + {{{24/120}}}A + 11
A = {{{109/120}}}A + 11
Multiply both sides by 120, get rid of the fraction
120A = 109A + 120(11)
120A - 109A = 1320
11A = 1320
A = 1320/11
A = 120 apples total