Question 569555
Let {{{x}}} be the larger even integer. The previous even integer would have been
{{{x-2}}}
We know that {{{(x-2)+3x=30}}} , so
{{{(x-2)+3x=30}}} --> {{{4x-2=30}}} --> {{{4x=32}}} --> {{{x=8}}}
The even integers are 6 and 8
Checking: {{{6+3*8=6+24=30}}}