<PRE><B>Question 569348</B>
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Let *[tex \Large x] represent the third of the consecutive odd integers.  Then the second is *[tex \Large x\ -\ 2] and the first is *[tex \Large x\ -\ 4].


The sum of the first and third is then *[tex \Large 2x\ -\ 4]


Five times the second is then *[tex \Large 5x\ -\ 10]


Less 63 is *[tex \Large 5x\ -\ 73]


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 4\ =\ 5x\ -\ 73]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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