<PRE><B>Question 569018</B>
One leg of a right traingle is 3 inches shorter than the hypotenuse. The other leg is equal to 8 inches. How long is the first leg? 
leg 1 : 8 
hypotenuse : x
leg 2 : x-3
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Pythagoras:
8^2 + (x-3)^2 = x^2
64 + x^2-6x+9 = x^2
6x = 73
x = 73/6 (hypotenuse)
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x-3 = (73/6)-(18/6) = 55/6
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Cheers,
Stan H.
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