Question 568943
How would I find the equation of an ellipse if I am give the foci(5,0) and (-5,0) and the length of major axis is 12
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Standard form of equation for ellipse with horizontal major axis: 
(x-h)^2/a^2+(y-k)^2/b^2=1,a>b, (h,k) being the (x,y) coordinates of the center.
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center: (0,0)
length of major axis=12=2a
a=6
a^2=36
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c=5
c^2=25
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c^2=a^2-b^2
b^2=a^2-c^2=36-25=11
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Equation of given ellipse:
x^2/36+y^2/11=1