Question 54468
-5(2x + 3y = 1)[Use the elimination method to solve for x and y]
+2(5x + 3y = 16)
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-10x-15y=-5
+10x+6y=32
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+0x-9y=27
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-9y=27 [Solve for y]
-9y/-9=27/-9
y=-3 [Plug (y=-3) back into the equations and solve for x]
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2x + 3y = 1
2x + 3(-3) = 1
2x+(-9)=1
2x=9+1
2x=10
x=10/2
x=5
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Plug the values of x and y back into either of the original equations.
5x + 3y = 16
5(5) + 3(-3) = 16
-9=-9 [Checks out]
or
2x + 3y = 1
2(5) + 3(-3) = 1
10-9=1
1=1 [Also checks out]