Question 568770
{{{ y = x^3 - 2x^2 + x - 1 }}}
{{{ y = -x^2 + 3x - 1 }}} 
By substitution:
{{{ x^3 - 2x^2 + x - 1 = -x^2 + 3x - 1 }}}
Add {{{1}}} to both sides
{{{ x^3 - 2x^2 + x  = -x^2 + 3x  }}}
{{{ x^3 - x^2 - 2x = 0 }}}
Factor out {{{ x }}}
{{{ x*( x^2 - x - 2 ) }}}
The solutions are:
{{{ x = 0 }}}
{{{ x^2 - x - 2 = 0 }}}
{{{ ( x - 2 )*( x + 1 ) = 0 }}}
{{{ x = 2 }}}
{{{ x = -1 }}}
You can verify these by plugging them
back into {{{ x^3 - x^2 - 2x = 0 }}}