Question 568618
<pre>
3x² + xy + 2y² = 0

(3)x² + (y)x + (2y²) = 0

a=3, b=y, c = 2y²

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

{{{x = (-y +- sqrt( y^2-4*3*2y^2 ))/(2*3) }}}

The 2 solutions are 

{{{x = (-y + sqrt( y^2-4*3*2y^2 ))/(2*3) }}} and {{{x = (-y - sqrt( y^2-4*3*2y^2 ))/(2*3) }}}

The first one is the same as choice (b)

Edwin</pre>