Question 568273
they are traveling at right angles to each other.									
At any given instant they form a right triangle with their starting point									
									
distance of one from starting point= x			North bound						
 other  = x+6			East bound						
									
X^2 +	(x+	6	}^2	=	30	^2			
				*					
X^2  +	X^2+	12	x	+	36	=	900		
									
2	X^2	+	12	x	-864	=	0	

/2
x^2+6x	-432
x^2+24x-18x-432=0

x(x+24)-18(x+24)=0
(x+24)(x-18)=0

x=24 OR 18
x=18 distance of north bound from starting point.

ignore negative since distance cannot be negative
distance of east bound will be  = 18+6 = 24 miles from the starting point