Question 568218
let the digits be x & y x in the tens place and y in the units place

x+y=11

The number is 10x+y

reversed
10y+x

10y+x= 10x+y +45

9y-9x=45
/9
y-x=5

x+y =11
y-x=5

add the two equations
2y=16
/2
x=8
if x = 8 then y= 3

the number is 83

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