<PRE><B>Question 568018</B>
Write the fraction in terms of the LCM of the denominators. 
9 over (x-1)^2 , 6 over x(x-1) 
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LCM = x(x-1)^2
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Rewrite each fraction with the LCM as its denominator
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[9/(x-1)^2] = [9x/LCM]
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[6/(x(x-1))] = [6(x+1)/LCM]
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Cheers,
Stan H.
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