Question 567988
I'll do the first one to get you started


# 1



Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(6,-2\right)]. So this means that {{{x[1]=6}}} and {{{y[1]=-2}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(1,3\right)].  So this means that {{{x[2]=1}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3--2)/(1-6)}}} Plug in {{{y[2]=3}}}, {{{y[1]=-2}}}, {{{x[2]=1}}}, and {{{x[1]=6}}}



{{{m=(5)/(1-6)}}} Subtract {{{-2}}} from {{{3}}} to get {{{5}}}



{{{m=(5)/(-5)}}} Subtract {{{6}}} from {{{1}}} to get {{{-5}}}



{{{m=-1}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(6,-2\right)] and *[Tex \LARGE \left(1,3\right)] is {{{m=-1}}}