Question 567717
27^(5-x) = 9^(x-2)


(3^3)^(5-x) = (3^2)^(x-2)


3^(3(5-x)) = 3^(2(x-2))


Since the bases are equal, the exponents are equal.


3(5-x)=2(x-2)


15-3x=2x-4


-3x=2x-4-15


-3x-2x=-4-15


-5x=-4-15


-5x=-19


x=(-19)/(-5)


x=19/5