Question 567426
From {{{8x^2-9x+5}}} we can see that {{{a=8}}}, {{{b=-9}}}, and {{{c=5}}}



{{{D=b^2-4ac}}} Start with the discriminant formula.



{{{D=(-9)^2-4(8)(5)}}} Plug in {{{a=8}}}, {{{b=-9}}}, and {{{c=5}}}



{{{D=81-4(8)(5)}}} Square {{{-9}}} to get {{{81}}}



{{{D=81-160}}} Multiply {{{4(8)(5)}}} to get {{{(32)(5)=160}}}



{{{D=-79}}} Subtract {{{160}}} from {{{81}}} to get {{{-79}}}



So the discriminant is {{{D=-79}}}



Since the discriminant is less than zero, this means that there are two complex solutions.



In other words, there are no real solutions.