Question 567836


{{{(3a+2)(a^2-3a+2)}}} Start with the given expression.



{{{3a(a^2-3a+2)+2(a^2-3a+2)}}} Expand.



{{{(3a)*(a^2)+(3a)*(-3a)+(3a)*(2)+(2)*(a^2)+(2)*(-3a)+(2)*(2)}}} Distribute.



{{{3*a^3-9*a^2+6*a+2*a^2-6*a+4}}} Multiply.



{{{3*a^3-7*a^2+4}}} Now combine like terms.



 So {{{(3a+2)(a^2-3a+2)}}} expands to {{{3*a^3-7*a^2+4}}}.



In other words, {{{(3a+2)(a^2-3a+2)=3*a^3-7*a^2+4}}}.