Question 567246
{{{A=(b-c)/(d-e)}}}



{{{A(d-e)=b-c}}}



{{{Ad-Ae=b-c}}}



{{{-Ae=b-c-Ad}}}



{{{Ae=-b+c+Ad}}}



{{{Ae=c-b+Ad}}}



{{{e=(c-b+Ad)/A}}}