Question 54411
The roots are -1,1,and 3 and the degree is 3.
(x=1)(x-1)(x-3)=0 when x=-1,1, or 3
Expand:
{{{f(x)=(x+1)(x-1)(x-3)}}}
{{{f(x)=(x^2-x+x-1)(x-3)}}}
{{{f(x)=(x^2-1)(x-3)}}}
{{{f(x)=x^2(x)+x^2(-3)-1(x)-1(-3)}}}
{{{highlight(f(x)=x^3-3x^2-x+3)}}}
Happy Calculating!!!