<PRE><B>Question 567603</B>
    an aeroplane takes off from the ground at an angle of 27 degrees and its average speed in the first 10 seconds is 200 km/h. what is the altitude of the plane at the end of this time?
.
Convert speed from hours to seconds:
200km/h * 1h/60min * 1min/60sec = 0.0556km/sec
.
Distance traveled:
10*0.0556km/sec = .5556 km
.
Let h = height
then
sin 27 = h/.5556
h = .5556(sin 27)
h = 0.0252 km
or
h = 25.2 m
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