Question 567535
perimeter of recatngle = 2(L+W)

2(L+W)=80

Area of rectangle = L*W

L*W= 300
L= 300/w

substitute L in the first equation

{{{2((300/W)+W)=80}}}


{{{2((300+W^2)/W)=80}}}


Multiply by W

{{{2(300+W^2)= 80W}}}

divide by 2


{{{300+W^2=40W


{{{W^2-40W+300)=0}}}


{{{W^2-30W-10W+300=0}}}

W(W-30)-10(W-30)=0

(W-30)(W-10)=0

W= 30 OR 10

The dimensions are 30m by 10m

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