Question 567516
a kayaker can paddle 12 mi in 2 h moving with the river current. paddling at the same pace, the trip back against the current takes 4 h. assume that the river current is constant. find what the kayaker's speed would be in still water.
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Downstream DATA:
distance = 12 miles ; time = 2 hours ; rate = 12/2 = 6 mph
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Upstream DATA:
distance = 12 miles ; time = 4 hrs ; rate = 12/4 = 3 mph
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Equations:
Downstream: b + c = 6
Upstream::: b - c = 3
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Add to get:
2b = 9
b = 4.5 mph (speed of the boat in still water.
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Solve for "c":
b + c = 6
4.5 + c = 6
c = 1.5 mph (speed of the current)
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Cheers,
Stan H.
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