Question 54404
SQRT48=SQRT16*3 & THE SQRT16*3=4SQRT3 REMOVING THE SQRT OF 16=4 OUTSIDE THE SQRT. 

THEN THE SQRT12=SQRT4*3 OR 2SQRT3 REMOVING THE SQRT OF 4=2 OUTSIDE THE SQRT.

SUBTRACTING 2SQRT3 FROM 4SQRT3 WE GET 2SQRT3