Question 567191
You invested $10,250.00, part of it in stock that paid 12.5% annual interest. However, the rest of the money suffered a 6.7% loss. If the total annual income from both investments was $346.00, how much was invested at each rate?
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Quantity Eq::: x + y = 10,250
Interest Eq::0.125x - 0.067y = 346
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Multiply thru the Interest equation by 1000
Multiply thru the Quantity Eq. by 125
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125x + 125y = 125*10,250
125x -  67y = 346000
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Subtract and solve for "y":
192y = $935,250
y = $4871.09 (amt. invested at 6.7%
Solve for "x":
x + y = 10,250
x + 4671.09 = 10,250
x = $5378.91 (amt. invested at 12.5%
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Cheers,
Stan H.
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