Question 566604
A vessel travelling on a compass course of 40 degrees at a speed of 28km/hr is being affected by a 3km/hr current from the east. What is the vessels resultant velocity?
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To solve, break speeds into horizontal and vertical components:
Horizontal component of 28km/hr=28cos50º=18 km/hr
Resulting horizontal component=18-speed of current=18-3=15km/hr
Vertical component of 28km/hr=28sin50º=21.5 km/hr
Resultant velocity of vessel=√(15^2+21.5^2)=√687=26.2 km/hr at compass heading of 35.4º