Question 566568
Solution A
Amount =121
Concentration =45% = 0.45

Solution B
Amount = 81 
Concentration =70% = 0.70

Mixture
Amount =(81+121)=202
Concentration =x

[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Mixture * Concentration of Mixture

(121)(0.45)+(81)(0.70)=(202)(x)
54.45+56.70=202x
111.15=202x
111.15/202=202x/202
0.550248=x
x=0.550248



Mixture
Amount =(81+121)=202
Concentration =x = 0.550248 = 0.550248/100 = 55.0248%


Chemist will have 202 of 55.0248% acid mixture.