Question 566186
<font face="Times New Roman" size="+2">


This one is set up for Substitution, but can easily be done by Elimination.


Substitution solution:


The second equation defines *[tex \Large y] in terms of *[tex \Large x], so substitute the RHS expression from the second equation in place of *[tex \Large y] in the first equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 5\left(\frac{1}{5}x\ +\ 1\right)\ =\ -15]


Solve for *[tex \Large x], then substitute the value back into either original equation (I suggest the second one since it gives you *[tex \Large y] directly) and solve for *[tex \Large y]


Elimination solution:


The first equation is already in Standard Form, i.e. *[tex \Large Ax\ +\ By\ =\ C] where A, B, and C are integers.  Put the second equation into Standard Form.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ 5y\ =\ -5]


Now add the two equations, term by term which will eliminate the *[tex \Large y] variable, leaving you with a single equation in *[tex \Large x].  Solve that and substitute back.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>