Question 566238
3h+4t = 12 cannot be solved for a unique solution because you have two variables and one equation, and this will yield infinitely many solutions. You can, however, solve for each variable. Suppose we want to solve for h. Then,


*[tex \LARGE 3h = 12 - 4t]


*[tex \LARGE h = \frac{12-4t}{3}]


Similarly, if we want to solve for t,


*[tex \LARGE 4t = 12-3h]


*[tex \LARGE t = \frac{12-3h}{4}]