Question 566079
Let the shadow at 45 deg be x
at 30 deg it is x+650 ft

let height of tower be h ft

Tan 45 = h/x

but tan 45 = 1
so h = x

Tan 30 = h/(h+650)

1/sqrt(3)= h/(h+650)

h+650 = h sqrt(3)
hsqrt(3)-h = 650

h(sqrt(3)-1)=650

h= 650/(sqrt(3)-1)

h= 888 ft