Question 566012
xy=3
y= 3/x

substitute y in the equation
5x-6y=6

5x -6*(3/x)=6

multiply the equation by x

5x^2-18=6x

5x^2-6x-18=0

Find the roots of the equation by quadratic formula								
								
a=	5	,	b=	-6	,	c=	-18	
								
b^2-4ac=	36	+	360					
b^2-4ac=	396		
{{{	sqrt(	396	)=	19.9	}}}
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	6	+	19.9	)/	10			
x1=	2.59							
x2=(	6		-19.9	) /	10			
x2= 	-1.39							


if x = 2.59 y = 3/2.59 = 1.16
(2.59,1.16)

If x= -1.39 y= 3/-1.39=-2.16
(-1.39,-2.16)